Matrix Games Forums

ORIGINAL: Taxman66

Hubert, I just recently observed a 2% (single chit {base 5, due to low tech level}) gain. This was with a mobilized Russia in July 1942 (and should have a +1 enemy catch up bonus to boot) in a current latest version pbem game.

This doesn't jive with your formula.

Research Progression % for a breakthrough determination, is multiplied by the number of chits applied. For example the UK has Infantry Weapons Level-0 with 1 chit invested, therefore the same 5% * 1 = 5% as above.

Thus, if a random number between 1-100 is determined to be less than 5%, a breakthrough is considered to have occurred. A breakthrough % is anywhere between [10,20] and can only occur after regular advancements are > 45%.

ORIGINAL: Hubert Cater

We are also considering displaying the advancement formula for each Major and for each research category where a research chit is applied.

It would be a mouse tool tip that displays when hovering over the chit investment area (highlighted in red) and would display something like the following:

[4,11] >> [3,8] +1 +1 +0

This would indicate the current advancement calculated [4,11], with the base value prior to catch up and intelligence bonuses applied, i.e. the [3,8]. The first + would be for friendly catch up, the second + for enemy catch up, and the third + for Spying and Intelligence bonus if applicable.

The benefit of this is it would be clear what the expected advancement results should be (also to confirm proper calculations), however the drawback is that it will reveal some extra information under FoW even though it is not clear which nation has the higher values for research level and for Spying and Intelligence.

But, overall both sides tended to know who had the better materiel, so it's not totally unrealistic and could outweigh the cons of knowing a bit more under FoW if everyone thought this would be useful?

PvtBenjamin wrote: Sat Jul 20, 2019 10:14 am

ORIGINAL: Taxman66

Hubert,

Preuming no bonus and the base range of 3 - 8, is the mean really 5.5 (with equal chances of each value appearing? Or is the formula/random number generation/rounding weighted to 5?

If weighted to 5, how does this work when bonuses increase the high end of the range more than they increase the low end of the range?

Glad you re visited this


If its equal weighted its 5 1/2.

If the mean is 5 its a log normal distribution with actually 3,4 occurring more than 6,7,8.

Its also possible 3,4,5,6,7 have the same probability and 8 an extremely small probability. This would be if there were fractions used in the RNG (random number generator) and the range is actually {2 1/2 to 7 1/2} then rounded. For example RNG returns 2.5000 - 3.4999 rounds to 3 but only 7.5000 - 7.5000 returns 8. Thousands of iterations would return a mean very close to 5.

Love to get in the weeds!