HE values in game are all wrong ?!
Posted: Sun Feb 23, 2003 6:13 pm
Hi gamers,
Continuing my searching for penetration/ballistics shells formulas I discovered that all the values in the game for HE ammo were WRONG !!!!
Maybe I'm wrong myself, but I redone the calculation dozens of times and I receive the same result: IN GAME THE PENETRATION VALUES FOR HE SHELLS WERE AT LEAST 200% MORE THAN REAL !!!!!!!!!!!!!!!!!!!!!!!
Have a look:
>>>Restricting ourselves to instantaneous-nose-fuzed (not hardened for armor impact and with no special delay, which were options in a few special-purpose impact nose fuzes used in WWII), HE-booster (trinitrophenol or more powerful booster explosive; not black-powder), Large-Cavity HE/HC projectiles without an ADF (including time fuzes and VT fuzes, which will act as such fuzes on impact), we get from U.S. and German tests the HE Projectile Armor Penetration Formula (No ADF) for blowing a caliber-wide or larger hole in the plate:
Tphe(noADF) = (2.576 x 10-20)(D)V5.6084COS[2(Ob2 - 45o)] + (0.156)(D)
assuming an STS plate of thickness Tphe hit by an HE projectile of diameter D (both in any units, as long as the same units are used for both Tphe and D) at a striking velocity of V in English feet/second units. "Ob2" in degrees is set to 45o if Ob is under 45o, eliminating the cosine term, and Ob2 is equal to Ob for values of Ob over 45o obliquity; this rapidly eliminates the effects of projectile velocity as the projectile is oriented more and more parallel to the plate at high obliquity and thus digs its nose in less and less on impact prior to the projectile detonating (under 45o obliquity, the nose dents the plate and digs in its nose into any plate thin enough to be subject to this formula). Note that the minimum plate thickness that will barely have a caliber-wide hole made in it even at zero striking velocity is 0.156 caliber of STS (1.25" for the 240-pound 8" HE projectile mentioned previously), with over 0.1872 caliber of STS (1.2 times 0.156 caliber, over 1.498" for the 8" HE projectile) needed to stop a through-crack in a dented STS plate. Note how little the striking velocity increases penetration until it nears the gun's muzzle velocity.
If the projectile has an ADF, but is otherwise identical, and is 10" or less in diameter, the following HE Projectile Armor Penetration Formula (ADF) gives a Tphe(ADF) value that replaces the above no ADF formula Tphe(noADF) value if and only if Tphe(ADF) is greater than Tphe(noADF); otherwise, always use Tphe(noADF):
Tphe(ADF) = [(0.00013333)(D)V + 0.033333]COS[2(Ob2 - 45o)]
with Tphe, D, V, and Ob2 defined as in the T(noADF) formula. This second formula is linear and from what I can figure out has to do with how deep the projectile nose can dig into the plate prior to detonating compared to the total length of the nose fuze and ADF. The ADF increases the delay by a more-or-less fixed amount and in a smaller projectile this allows a much lower striking velocity for the nose to dig into the plate deep enough prior to exploding so that the upper end of the main explosive cavity itself is touching the plate when the explosion occurs, allowing the main filler charge to assist directly in blowing open the hole, while for larger (over-10") HE/HC projectiles with an ADF, the much larger nose does not dig deep enough even with the added delay until the striking velocity increases considerably, eliminating this effect, so the projectile fragments must blow open the hole by themselves, though obviously assisted by the filler blast behind them.
>>>>>>>>
Now, when make calculation for example for 150 mm HE nofused shell and supposing the speed at 1500 feet/second the first formula give us in the best circumstances (obliquity=45) MAX. 25mm armor penetration !!!!!!!!!!!!!!!!!!!!!
If we supposed the same shell but timefused (with ADF, but very rare utilized in ww2 for HE) the value is MAX. 30mm penetration !!!!!!!!!!!!!!!!!!!!!!
Now look at the most HE penetration values for 150mm in game: these are aprox. 58mm ?????????????????????????? It's almost 200% more than the calculations.......
Of course, I supposed the armour been a hardened one, not mild steel !
In which consist this big difference ? Because if I have right all the game basis for HE is false......and we make dreams about battles in ww2 !!!!!!!!!!!!!!!!
Please take a look and comment my problem.
Leo.
Continuing my searching for penetration/ballistics shells formulas I discovered that all the values in the game for HE ammo were WRONG !!!!
Maybe I'm wrong myself, but I redone the calculation dozens of times and I receive the same result: IN GAME THE PENETRATION VALUES FOR HE SHELLS WERE AT LEAST 200% MORE THAN REAL !!!!!!!!!!!!!!!!!!!!!!!
Have a look:
>>>Restricting ourselves to instantaneous-nose-fuzed (not hardened for armor impact and with no special delay, which were options in a few special-purpose impact nose fuzes used in WWII), HE-booster (trinitrophenol or more powerful booster explosive; not black-powder), Large-Cavity HE/HC projectiles without an ADF (including time fuzes and VT fuzes, which will act as such fuzes on impact), we get from U.S. and German tests the HE Projectile Armor Penetration Formula (No ADF) for blowing a caliber-wide or larger hole in the plate:
Tphe(noADF) = (2.576 x 10-20)(D)V5.6084COS[2(Ob2 - 45o)] + (0.156)(D)
assuming an STS plate of thickness Tphe hit by an HE projectile of diameter D (both in any units, as long as the same units are used for both Tphe and D) at a striking velocity of V in English feet/second units. "Ob2" in degrees is set to 45o if Ob is under 45o, eliminating the cosine term, and Ob2 is equal to Ob for values of Ob over 45o obliquity; this rapidly eliminates the effects of projectile velocity as the projectile is oriented more and more parallel to the plate at high obliquity and thus digs its nose in less and less on impact prior to the projectile detonating (under 45o obliquity, the nose dents the plate and digs in its nose into any plate thin enough to be subject to this formula). Note that the minimum plate thickness that will barely have a caliber-wide hole made in it even at zero striking velocity is 0.156 caliber of STS (1.25" for the 240-pound 8" HE projectile mentioned previously), with over 0.1872 caliber of STS (1.2 times 0.156 caliber, over 1.498" for the 8" HE projectile) needed to stop a through-crack in a dented STS plate. Note how little the striking velocity increases penetration until it nears the gun's muzzle velocity.
If the projectile has an ADF, but is otherwise identical, and is 10" or less in diameter, the following HE Projectile Armor Penetration Formula (ADF) gives a Tphe(ADF) value that replaces the above no ADF formula Tphe(noADF) value if and only if Tphe(ADF) is greater than Tphe(noADF); otherwise, always use Tphe(noADF):
Tphe(ADF) = [(0.00013333)(D)V + 0.033333]COS[2(Ob2 - 45o)]
with Tphe, D, V, and Ob2 defined as in the T(noADF) formula. This second formula is linear and from what I can figure out has to do with how deep the projectile nose can dig into the plate prior to detonating compared to the total length of the nose fuze and ADF. The ADF increases the delay by a more-or-less fixed amount and in a smaller projectile this allows a much lower striking velocity for the nose to dig into the plate deep enough prior to exploding so that the upper end of the main explosive cavity itself is touching the plate when the explosion occurs, allowing the main filler charge to assist directly in blowing open the hole, while for larger (over-10") HE/HC projectiles with an ADF, the much larger nose does not dig deep enough even with the added delay until the striking velocity increases considerably, eliminating this effect, so the projectile fragments must blow open the hole by themselves, though obviously assisted by the filler blast behind them.
>>>>>>>>
Now, when make calculation for example for 150 mm HE nofused shell and supposing the speed at 1500 feet/second the first formula give us in the best circumstances (obliquity=45) MAX. 25mm armor penetration !!!!!!!!!!!!!!!!!!!!!
If we supposed the same shell but timefused (with ADF, but very rare utilized in ww2 for HE) the value is MAX. 30mm penetration !!!!!!!!!!!!!!!!!!!!!!
Now look at the most HE penetration values for 150mm in game: these are aprox. 58mm ?????????????????????????? It's almost 200% more than the calculations.......
Of course, I supposed the armour been a hardened one, not mild steel !
In which consist this big difference ? Because if I have right all the game basis for HE is false......and we make dreams about battles in ww2 !!!!!!!!!!!!!!!!
Please take a look and comment my problem.
Leo.