ORIGINAL: inqistor
There are no such probabilities. What would be point in calculating distance of lethal radius for bomb? Who cares, movie makers? There are different distances for sides, front, and back of vector. Totally useless value.ORIGINAL: herwin
Just curious, because 10% hit probability comes up. Is that the distance to the 10% lethality contour? Or is that (slightly different) a 10% probability of a fragment impacting on an exposed soft target with enough energy to cause a casualty?
What army REALLY calculates is called VULNERABLE AREA. It is defined as area (in square feet) on which the average
density of throughs and deep strikes on vertical wooden targets is 1 per 10 square feet. (deep strikes is penetration of at least ONE inch)
Example document you are seeking for:
Ministry of Supply and War Office: Military Operational Research Unit
A theory of fragmentation: comparison with observed fragmentations of service bombs and shells
Covering dates 1943
Report No: 138
Protection is listed for that much of steel plate. Values are VULNERABLE AREA in square feet.
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You have me a bit confused. Of course, terminal ballistics were historically a bit confused. However, your definition of vulnerable area makes sense when one realises that measurement of lethality is rather fraught and sensitive to the exact circumstances of the shell exploding. Most experimental studies have to use second or third order proxies for the parameter of interest. If you were to investigate why the exact measure reported is chosen, you discover a long chain of assumptions, probably extending back to studies during 1920-1940 using live pigs or goats.





