g-force

[DamoclesX]

just thought of it.

It might be a cool addon, thought of it as I was balancing the viperm1, since you can spin these babys out of control, I figured it would be cool to black and and possible kill your pilot if you mashed the stick to hard and flung her into a 20 g spin

[Darkhawkt]

One minor problem: in atmospheric missions (there are no G problems in space) you already can pull 40-60+ Gs. If you were to add blackouts and redouts, you would have to change quite a bit, wouldn't you?

[Diabolico]

... besides it is expected that on such advance times that technology has found a way to compensate for accelaration and other forces, as gravity has obviously been mastered.[:-]
Though Damocles's idea could be interesting to explore if damaged was added to the gravity generators (or whatever compensates for G-force, gravity and so on), that pilots could indeed suffer from blackouts, etc...
But perhaps there are more important priorities like code, MP issues, Battleships ([:D]) and so on...

=S=

[DamoclesX]

nothing is going to compenstate for going from 0g to 50 in half a second

you are superheated plasma, period lol

[Pheonix Starflare]

ORIGINAL: Darkhawkt
(there are no G problems in space)

Hate to break it to ya, but Newton's Laws are still valid in space. If someone accelerates at 40g's, they will be smushed flat. No question. Now, SS may very well have some 'inertial compensators' or somesuch that reduces or eliminates the g-loads achievable by these spacecraft. This does not mean that there are no g-forces in space, however.

The term "g's" is a tad misleading, but it is simply a measure of acceleration relative the the acceleration due to gravity near the Earth's surface (that's what causes all objects, neglecting air resistance, to fall at the same speed/hit the ground at the same time.)

Newton's Second law, most commonly written F=ma (also known as dp/dt, if you like calculus) simply means that the net force on an object (could be gravity minus air resistance, or just the rocket thrust in space) means that for a given force, F, an object of mass m will undergo an acceleration, a. So, for a mass of 1000 kg to accelerate at 3 g's (1 g = 9.8 m/s/s) it requires a force of .... 29,400 N (N = Newton or, 1 kgm/s/s) (1 N = .225 lb, or 1 lb = 4.4 N).

[Diabolico]

Very well put... [:D]
But I still prefer inertial compensators... [:D]

[Pheonix Starflare]

Quite true. However, if we had inertial compensators, why would we have 'g' problems in the atmosphere?

[Diabolico]

Brilliant![:D]... perhaps.. huh... if those compensators stopped working for some reason? [;)]

[DamoclesX]

perhaps you better "surrender" to my idea of over-g and death...

[:D][:D][:D][:D]

[Diabolico]

[:D]

[Pheonix Starflare]

Muahahahahah!
Physics and logic triumph over all!

...now to study for my calc final...[&:]

[DamoclesX]

I just got through mine

got a 96 in the class lol.

What level of calc are you taking? I was in second year, integration, volume through calc, moment of intertia, finding work, partial fractions, that kind of jazz

[Pheonix Starflare]

My calc class

It's basically 'calc 1,' but they expect everyone there has taken calc before.

[Diabolico]

And may the force be with you (for your finals)!
You will need it!!! [:D]

Now ace those finals and get your royal asses back here to play SS!
Good luck!

=S=[;)]